Return all possible palindrome partitioning of s.
For example, given s =
"aab"
,Return
[ ["aa","b"], ["a","a","b"] ]
Initial attempt:
class Solution {
public:
bool palindrome(string s)
{
int len = s.size();
for (int i=0;i<len/2; i++)
{
if (s[i]!=s[len-i])
return false;
}
return true;
}
void helper( int i, string s, vector<string> &p, vector<vector<string>> &ret)
{
int slen = s.size();
if (i==slen-1&&flag)
{
ret.push_back(p);
}
for (int k=i; k<slen; k++)
{
if (palindrome(s.substr(0,k)))
{
p.push_back(s.substr(0,k)); //Got stuck
}
}
i++;
}
vector<vector<string>> partition(string s) {
vector<vector<string>> ret;
int len=s.size();
if (len==0) return ret;
vector<string> p;
helper(0,s,p,ret);
return ret;
}
};
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